integral of sin^2(x) ∫sin²x dx | sin^2

The integral of sin^2(x) can be evaluated using the identity:

sin^2(x) = {1 – cos(2x)}/2

Substituting this identity into the integral, we get:

∫ sin^2(x) dx = ∫ {1 – cos(2x)}/2 dx

= (1/2) ∫ (1 – cos(2x)) dx

= (1/2) {x – (1/2) sin(2x)} + C

where C is the constant of integration.

Therefore, the integral of sin^2(x) is:

∫ sin^2(x) dx = (1/2) {x – (1/2) sin(2x)} + C.